Extension for Converting and Adding Days to Dates

Article Overview:

This article will cover how you can achieve the following:

• Convert ISO date strings into the YYYY-MM-DD format.
• Add a specific number of days to a date for dynamic test scenarios.

Problem Statement:

Test cases often involve converting ISO date strings (e.g., 2021-03-03T08:24:51Z) into simpler formats like YYYY-MM-DD or adding a certain number of days to a date dynamically.

Solution:

Use the DateExt(datetime, days) extension to:

1. Convert ISO dates into YYYY-MM-DD format.
2. Add a specified number of days to a given date.

• Extension Name: DateExt(datetime, days)
• Purpose: Handles date conversion and day addition.
• Code:

  var date = new Date(datetime);
  // Convert 'days' (which is a string) to a number
  var daysNumber = Number(days); // or use parseInt(days, 10);
  // Add the number of days to the current date
  date.setDate(date.getDate() + daysNumber);
  // Return the formatted date as 'YYYY-MM-DD'
  return (date.getFullYear() + '-' + 
          ((date.getMonth() > 8) ? (date.getMonth() + 1) : ('0' + (date.getMonth() + 1))) + '-' + 
          ((date.getDate() > 9) ? date.getDate() : ('0' + date.getDate())));
  

• Reference Screenshot:

Examples:

1. Convert ISO Date to YYYY-MM-DD:

• Scenario: Convert 2021-03-03T08:24:51Z to 2021-03-03.
• Code Example:
   

  DateExt("2021-03-03T08:24:51Z", "")
• Output: 2021-03-03
• Reference Screenshot: 

2. Add Days to an ISO Date:

• Scenario: Add 7 days to 2021-03-03T08:24:51Z.
• Code Example:
   

  DateExt("2021-03-03T08:24:51Z", "7")
• Output: 2021-03-10
• Reference Screenshot:

Notes:

• The datetime parameter must be in ISO format.
• Use the days parameter to specify the number of days to add dynamically.
• This extension simplifies date-related test scenarios, including future and past date calculations.